Answer
$[-2, 2]$
Work Step by Step
RECALL:
The function $f(x) = a \cdot \sin{(bx+c)}$ has an amplitude of $|a|$, which means that the value of $f(x)$ range from $-|a|$ to $|a|$.
The function $f(x)=2 \sin {(bx+c)}$ has an amplitude of $|2|=2$.
Thus, the values of $f(x)$ range from $-2$ to $2$.
The range of the given function is $[-2, 2]$.
