Answer
$38^{\circ}$F
Work Step by Step
Since April $5$ corresponds to Day $95$, we substitute $x=95$ in the formula:
$T(95)=37+21\sin[\frac{2\pi}{365}(x-91)]$
$T(95)=37+21\sin[\frac{2\pi}{365}(95-91)]$
$T(95)=37+21\sin[\frac{2\pi}{365}(4)]$
$T(95)=37+21\sin[0.0689]$
$T(95)=37+21(0.0688)$
$T(95)=37+1.45$
$T(95)=38.45\approx38^{\circ}$F
Therefore, on Day $95$, the temperature is $38^{\circ}$F.