Answer
amplitude = $1$
period = $120^o$ or $\frac{2}{3}\pi$
Work Step by Step
The given graph shows around two periods of the sine function.
Since the highest point is equivalent to two squares from the x-axis, and each square representing 0.5, then the amplitude is:
$=2 \times 0.5
\\=1$
Horizontally, one period of the graph is from the y-axis (or $x=0$) up to the edge of the fourth square to the right of the y-axis.
.
Since each square represents $30^o$ or $\frac{\pi}{6}$, then the period of the given function is:
$=30^o \times 4
\\=120^o$
or
$=\frac{\pi}{6} \times 4
\\=\frac{2}{3}\pi$
