## Trigonometry (10th Edition)

The temperature on June 15 is $58.3^{\circ}F$
June 15 is day 166, so we can use $x = 166$ in the equation: $T(x)=37~sin[\frac{2\pi}{365}~(x−101)]+25$ $T(166)=37~sin[\frac{2\pi}{365}~(166−101)]+25$ $T(166)=37~sin[1.119]+25$ $T(166)=(37)(0.900)+25$ $T(166) = 58.3^{\circ}F$ The temperature on June 15 is $58.3^{\circ}F$