Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 3 - Radian Measure and the Unit Circle - Section 3.3 The Unit Circle and Circular Functions - 3.3 Exercises: 86d

Answer

The temperature on June 15 is $58.3^{\circ}F$

Work Step by Step

June 15 is day 166, so we can use $x = 166$ in the equation: $T(x)=37~sin[\frac{2\pi}{365}~(x−101)]+25$ $T(166)=37~sin[\frac{2\pi}{365}~(166−101)]+25$ $T(166)=37~sin[1.119]+25$ $T(166)=(37)(0.900)+25$ $T(166) = 58.3^{\circ}F$ The temperature on June 15 is $58.3^{\circ}F$
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