#### Answer

The temperature on Day 150 is $52.6^{\circ}F$

#### Work Step by Step

We can use $x = 150$ in the equation:
$T(x)=37~sin[\frac{2\pi}{365}~(x−101)]+25$
$T(150)=37~sin[\frac{2\pi}{365}~(150−101)]+25$
$T(150)=37~sin[0.8435]+25$
$T(150)=(37)(0.747)+25$
$T(150) = 52.6^{\circ}F$
The temperature on Day 150 is $52.6^{\circ}F$