## Trigonometry (10th Edition)

The temperature on Day 150 is $52.6^{\circ}F$
We can use $x = 150$ in the equation: $T(x)=37~sin[\frac{2\pi}{365}~(x−101)]+25$ $T(150)=37~sin[\frac{2\pi}{365}~(150−101)]+25$ $T(150)=37~sin[0.8435]+25$ $T(150)=(37)(0.747)+25$ $T(150) = 52.6^{\circ}F$ The temperature on Day 150 is $52.6^{\circ}F$