Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 3 - Radian Measure and the Unit Circle - Section 3.3 The Unit Circle and Circular Functions - 3.3 Exercises: 86c

Answer

The temperature on Day 150 is $52.6^{\circ}F$

Work Step by Step

We can use $x = 150$ in the equation: $T(x)=37~sin[\frac{2\pi}{365}~(x−101)]+25$ $T(150)=37~sin[\frac{2\pi}{365}~(150−101)]+25$ $T(150)=37~sin[0.8435]+25$ $T(150)=(37)(0.747)+25$ $T(150) = 52.6^{\circ}F$ The temperature on Day 150 is $52.6^{\circ}F$
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