Answer
$43^{o}N$
Work Step by Step
Arc length s (for central angle $\theta$):$ \quad s=r\theta$, where $\theta$ is in radians
Converting between Degrees and Radians
1. Multiply a degree measure by $\displaystyle \frac{\pi}{180}$ radian and simplify to convert to radians.
2. Multiply a radian measure by $\displaystyle \frac{180^{\mathrm{o}}}{\pi}$ and simplify to convert to degrees.
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$r=6400$ km, $s=1100$ km
$ s=r\theta,\ \quad$ ... solve for $\theta$
$ 1100=6400\theta$
$\displaystyle \theta=\frac{1100}{6400}=\frac{11}{64}$ (...radians...)
see case 2 of converting ....
$\displaystyle \theta=\frac{11}{64}\cdot\frac{180^{\mathrm{o}}}{\pi}\approx$9.84771210381$\approx 10^{o}$
The north-south angle between the two cities is about $10^{o}..$
(Toronto lies about $10^{o}$ north of Charleston)
Latitude of Toronto $\approx 33^{o}+10^{o}=43^{o}N$
