Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 2 - Acute Angles and Right Triangles - Section 2.5 Further Applications of Right Triangles - 2.5 Exercises - Page 84: 41b

Answer

The distance between $M$ and $N$ is $R~[1 - cos(\frac{\theta}{2})]$

Work Step by Step

We can find an expression for the length of the line $CN$: $\frac{CN}{R} = cos(\frac{\theta}{2})$ $CN = (R)~cos(\frac{\theta}{2})$ Note that the length of the line $CM$ is equal to $R$. Note also that the distance between $M$ and $N$ is $CM-CN$. We can find an expression for the distance between $M$ and $N$: $CM - CN = R - (R)~cos(\frac{\theta}{2})$ $CM - CN = R~[1 - cos(\frac{\theta}{2})]$ The distance between $M$ and $N$ is $R~[1 - cos(\frac{\theta}{2})]$
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