Answer
$\angle A = 36^{\circ}$
$\angle B = 54^{\circ}$
Work Step by Step
We can find $\angle A$:
$tan ~A = \frac{BC}{AC}$
$tan ~A = \frac{1.0837~mi}{1.4923~mi}$
$\angle A = tan^{-1}(\frac{1.0837~mi}{1.4923~mi})$
$\angle A = 36^{\circ}$
We can find $\angle B$:
$\angle A + \angle B + \angle C = 180^{\circ}$
$\angle B = 180^{\circ} -\angle A - \angle C$
$\angle B = 180^{\circ} -36^{\circ} - 90^{\circ}$
$\angle B = 54^{\circ}$
