## Trigonometry (10th Edition)

1. $R= \frac{v^{2}}{g(f+\tan\theta)}$ 2. Solving for v $v= \sqrt {gR(f+\tan\theta)}$ 3. $R=1150$; $\theta = 2.1^{\circ}$; $g = 32.2$ and$f= 0.4$ $v= \sqrt {gR(f+\tan\theta)}=\sqrt {1150\times 32.2 \times(0.14+\tan 2.1^{\circ})} = 80.9 ft/s$ 4. Converting to mph: $v= 80.9 ft/s = \frac{80.9}{3600}\times 5280 = 55 mph$