## Trigonometry (10th Edition)

Published by Pearson

# Chapter 2 - Acute Angles and Right Triangles - Section 2.3 Finding Trigonometric Function Values Using a Calculator - 2.3 Exercises - Page 66: 68

55 mph

#### Work Step by Step

1. $R= \frac{v^{2}}{g(f+\tan\theta)}$ 2. Solving for v $v= \sqrt {gR(f+\tan\theta)}$ 3. $R=1150$; $\theta = 2.1^{\circ}$; $g = 32.2$ and$f= 0.4$ $v= \sqrt {gR(f+\tan\theta)}=\sqrt {1150\times 32.2 \times(0.14+\tan 2.1^{\circ})} = 80.9 ft/s$ 4. Converting to mph: $v= 80.9 ft/s = \frac{80.9}{3600}\times 5280 = 55 mph$

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