Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 2 - Acute Angles and Right Triangles - Section 2.3 Finding Trigonometric Function Values Using a Calculator - 2.3 Exercises - Page 66: 67b

Answer

1701 ft

Work Step by Step

1. Since there are 5280 ft in one mile and 3600 s in one hour we convert as $v=70mph = \frac{70 mph}{1hr}\times\frac{1hr}{3600s}\times 5280 = 102.67 ft/s$ 2. $R=\frac{v^{2}}{g(f + tan\theta)}$ $\theta=3^{\circ}$; $g = 32.2$ and $ f= 0.14$ $R=\frac{v^{2}}{g(f + tan\theta)}= \frac{102.67^{2}}{32.2(0.14 + tan 3^{\circ})}= 1701 ft$
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