Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 2 - Acute Angles and Right Triangles - Section 2.2 Trigonometric Functions of Non-Acute Angles - 2.2 Exercises - Page 59: 52

Answer

$\cot$$^{2}$ 135$^{\circ}$ + $\tan$$^{4}$ 60$^{\circ}$ - $\sin$$^{4}$ 180$^{\circ}$ = 10

Work Step by Step

$\cot$$^{2}$ 135$^{\circ}$ + $\tan$$^{4}$ 60$^{\circ}$ - $\sin$$^{4}$ 180$^{\circ}$ $\cot$ 135$^{\circ}$ = -1 $\tan$ 60$^{\circ}$ = $\sqrt3$ $\sin$ 180$^{\circ}$ = 0 = (-1)$^{2}$ + ($\sqrt3$)$^{4}$ - (0)$^{4}$ = 1 + 9 + 0 = 10 Therefore: $\cot$$^{2}$ 135$^{\circ}$ + $\tan$$^{4}$ 60$^{\circ}$ - $\sin$$^{4}$ 180$^{\circ}$ = 10
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