Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 2 - Acute Angles and Right Triangles - Section 2.2 Trigonometric Functions of Non-Acute Angles - 2.2 Exercises: 13


$\sin$ 60^{\circ} = $\frac{\sqrt3}{2}$ $\cot$ 60^{\circ} = $\frac{\sqrt3}{3}$ $\csc$ 60^{\circ} = $\frac{\sqrt3}{2}$

Work Step by Step

60^{\circ} $\sin$ 60^{\circ} = $\frac{Opposite}{Hypotenuse}$ = $\frac{\sqrt3}{2}$ $\cot$ 60^{\circ} = $\frac{Adjacent}{Opposite}$ = $\frac{\sqrt3}{3}$ $\csc$ 60^{\circ} = $\frac{Hypotenuse}{Opposite}$ = $\frac{\sqrt3}{2}$
Small 1475159887
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.