Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Appendix D - Graphing Techniques - Exercises - Page 446: 27b

Answer

Point = $(32, 12)$

Work Step by Step

Given that point $(8, 12)$ is on the graph of $y = f(x)$ and it can be seen that the graph of $y = f(\frac{1}{4} x)$ is the horizontal stretching of the graph of $y = f(x)$ by $4$ times, One point on the graph of $y = f(\frac{1}{4} x)$ will be $(32, 12)$ because for every point $(x, y)$ on the graph of $y = f(x)$, there will be a corresponding point $(4x, y)$ on the graph of $y = f(\frac{1}{4} x)$ .
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