Appendix D - Graphing Techniques - Exercises - Page 446: 16

Appendix D - 16 (Answer) See Graph I

Appendix D - 16 (Solution) For $y = -\frac{1}{3} x^2$, When $x = 6, y = -12;$ $x = 3, y = -3;$ $x = 0, y = 0;$ $x = −3, y = -3;$ $x = −6, y = -12$ Domain = $(−\infty, \infty)$ Range = $(-\infty, 0]$ See Graph I