Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Appendix D - Graphing Techniques - Exercises - Page 446: 26b

Answer

Point = $(8, 48)$

Work Step by Step

Given that point $(8, 12)$ is on the graph of $y = f(x)$ and it can be seen that the graph of $y = 4 f(x)$ is the vertical stretching of the graph of $y = f(x)$ by $4$ times, One point on the graph of $y = 4 f(x)$ will be $(8, 48)$ because for every corresponding $x$-values on the graph of $y = f(x)$, the $y$-values of the graph of $y = 4 f(x)$ are each $4$ times those of $y = f(x)$.
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