Answer
$\frac{1}{2}$ $\geq$ $x$ or $x$ $\leq$ $\frac{1}{2}$
The equivalent interval notation is $(-\infty, \frac{1}{2}]$.
Work Step by Step
$\frac{2x - 5}{-8}$ $\leq$ $1 - x$
$2x - 5$ $\geq$ $-8(1 - x)$ Inequality sign reversed because of multiplication of -8
$2x - 5$ $\geq$ $-8 + 8x$
$8 - 5$ $\geq$ $8x - 2x$
$3$ $\geq$ $6x$
$\frac{3}{6}$ $\geq$ $x$
$\frac{1}{2}$ $\geq$ $x$ or $x$ $\leq$ $\frac{1}{2}$
The equivalent interval notation is $(-\infty, \frac{1}{2}]$.
