Answer
This inequality holds for other intervals of $x$ with interval notation $[\frac{-11}{5}, \infty).$
Work Step by Step
$\frac{4x + 7}{-3} \leq (2x + 5)$
$(4x + 7) \geq -3(2x + 5)$ Multiplication of negative number
$4x + 7 \geq -6x - 15$
$4x + 7 + 6x + 15 \geq 0$
$10x + 22 \geq 0$
$10x \geq -22$
$x \geq \frac{-22}{10}$
$x \geq \frac{-11}{5}$
This inequality holds for other intervals of $x$ with interval notation $[\frac{-11}{5}, \infty).$
