Answer
Equation A, {$-\frac{1}{3},6$}
Work Step by Step
Equation A is written in a form in which it can be immediately compared to the standard form of the quadratic equation $ax^{2}+bx+c=0$ and the values of $a$,$b$ and $c$ can be determined for use in the quadratic formula.
Step 1: By comparison, $a=3$, $b=-17$ and $c=-6$.
Step 2: Inserting these values in the quadratic formula
$x=\frac{-b\pm\sqrt (b^{2}-4ac)}{2a}$
Step 3: $x=\frac{-(-17)\pm\sqrt ((-17)^{2}-4(3)(-6))}{2(3)}$
Step 4: $x=\frac{17\pm\sqrt (289+72)}{6}$
Step 5: $x=\frac{17\pm\sqrt (361)}{6}$
Step 6: $x=\frac{17\pm19}{6}$
Step 7: $x=\frac{17+19}{6}$ or $x=\frac{17-19}{6}$
Step 8: $x=\frac{36}{6}$ or $x=\frac{-2}{6}$
Step 9: $x=6$ or $x=-\frac{1}{3}$
Step 10: Therefore, the solution set of the equation is {$-\frac{1}{3},6$}.
