Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Appendix A - Equations and Inequalities - Exercises - Page 416: 11

Answer

{$-\frac{2}{7}$}

Work Step by Step

Step 1: $\frac{5}{6}x-2x+\frac{4}{3}=\frac{5}{3}$ Step 2: Multiplying both sides by 6, the LCD of the fractions: $6(\frac{5}{6}x-2x+\frac{4}{3})=6(\frac{5}{3})$ Step 3: $6(\frac{5}{6}x)-6(2x)+6(\frac{4}{3})=6(\frac{5}{3})$ Step 4: $5x-12x+8=10$ Step 5: $-7x+8=10$ Step 6: Subtracting 8 from both sides, $-7x+8-8=10-8$ Step 7: $-7x=2$ Step 8: Dividing both sides by $-7$, $\frac{-7x}{-7}=\frac{2}{-7}$ Step 9: $x=-\frac{2}{7}$ Check: Step 1: Substituting the answer in the initial equation, $\frac{5}{6}(-\frac{2}{7})-2(-\frac{2}{7})+\frac{4}{3}=\frac{5}{3}$ Step 2: $(-\frac{10}{42})+\frac{4}{7}+\frac{4}{3}=\frac{5}{3}$ Step 3: $(-\frac{5}{21})+\frac{4}{7}+\frac{4}{3}=\frac{5}{3}$ Step 4: $\frac{-5+4(3)+7(4)}{21}=\frac{5}{3}$ Step 5: $\frac{-5+12+28}{21}=\frac{5}{3}$ Step 6: $\frac{35}{21}=\frac{5}{3}$ Step 7: $\frac{5}{3}=\frac{5}{3}$ Since the solution checks, the solution set is {$-\frac{2}{7}$}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.