Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 8 - Review Exercises - Page 411: 78

Answer

$x = 5~cos~t+3$ $y = 5~sin~t+4$ where $t$ in $[0,2\pi]$

Work Step by Step

We can find $r$: $r = \sqrt{3^2+4^2} = \sqrt{25} = 5$ We can write parametric equations for a circle of radius 5 centered on the origin: $x = r~cos~t = 5~cos~t$ $y = r~sin~t = 5~sin~t$ where $t$ in $[0,2\pi]$ For the circle to be centered on the point (3,4), the x-values must be translated 3 units in the positive x-direction, and the y-values must be translated 4 units in the positive y-direction. We can write parametric equations for a circle of radius 5 centered on the point (3,4): $x = 5~cos~t+3$ $y = 5~sin~t+4$ where $t$ in $[0,2\pi]$
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