Chapter 8 - Review Exercises - Page 411: 74

$x = 3y+5$, where $y$ in $[-6,4]$

$y = t-1$ $t = y+1$ We can replace this expression in the equation for $x$: $x = 3t+2$ $x = 3(y+1)+2$ $x = 3y+5$ Since $t$ in $[-5,5]$, then $y$ in $[-6,4]$ $x = 3y+5$, where $y$ in $[-6,4]$