Answer
$2-3i$
Work Step by Step
Step 1: We will multiply both the numerator and the denominator by the complex conjugate of the denominator. Also, the conjugate of $i$ is $-i$.
Step 2: $\frac{3+2i}{i}\times\frac{-i}{-i}=\frac{-i(3+2i)}{-i^{2}}=\frac{-3i-2i^{2}}{-(-1)}=\frac{-3i-2(-1)}{1}=2-3i$
