Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 8 - Complex Numbers, Polar Equations, and Parametric Equations - Section 8.5 Polar Equations and Graphs - 8.5 Exercises - Page 395: 65

Answer

$(x+1)^2 +(y+1)^2 = 2$ We can see the graph below:
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Work Step by Step

$r = -2~cos~\theta-2~sin~\theta$ $\sqrt{x^2+y^2} = -\frac{2x}{\sqrt{x^2+y^2}}-\frac{2y}{\sqrt{x^2+y^2}}$ $x^2+y^2 = -2x-2y$ $x^2+2x+y^2+2y = 0$ $(x+1)^2 +(y+1)^2 = 2$ We can see the graph below:
Small 1529899744
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