Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 8 - Complex Numbers, Polar Equations, and Parametric Equations - Section 8.5 Polar Equations and Graphs - 8.5 Exercises - Page 395: 65


$(x+1)^2 +(y+1)^2 = 2$ We can see the graph below:

Work Step by Step

$r = -2~cos~\theta-2~sin~\theta$ $\sqrt{x^2+y^2} = -\frac{2x}{\sqrt{x^2+y^2}}-\frac{2y}{\sqrt{x^2+y^2}}$ $x^2+y^2 = -2x-2y$ $x^2+2x+y^2+2y = 0$ $(x+1)^2 +(y+1)^2 = 2$ We can see the graph below:
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.