Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 8 - Complex Numbers, Polar Equations, and Parametric Equations - Section 8.5 Polar Equations and Graphs - 8.5 Exercises - Page 395: 64


$y = \frac{x^2}{6}-1.5$ We can see the graph below:

Work Step by Step

$r = \frac{3}{1-sin~\theta}$ $r-r~sin~\theta = 3$ $\sqrt{x^2+y^2}-y = 3$ $\sqrt{x^2+y^2} = y+3$ $x^2+y^2 = y^2+6y+9$ $x^2 = 6y+9$ $y = \frac{x^2}{6}-1.5$ We can see the graph below:
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