Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 8 - Complex Numbers, Polar Equations, and Parametric Equations - Section 8.4 De Moivre's Theorem: Powers and Roots of Complex Numbers - 8.4 Exercises - Page 382: 11

Answer

$=(\frac{27}{2}-i.\frac{27\sqrt 3}{2})$

Work Step by Step

De Moivre’s Theorem states that when $ r (\cos\theta+i \sin\theta)$ is a complex number, and if $n$ is any real number, then the following relationship holds. $[ r (\cos\theta+i \sin\theta)]^{n}=[ r^{n} (\cos n\theta+i \sin n\theta)]$ In compact form, this is written $[ r cis\theta]^{n}=[ r^{n} (cis \theta)]$ $[ 3 cis100^{\circ}]^{3}=[ 3^{3} (cis 100^{\circ})]$ $[27 (\cos 100^{\circ}+i \sin 100^{\circ})]$ $=[ 27(\frac{1}{2}-i.\frac{\sqrt 3}{2})]$ $=(\frac{27}{2}-i.\frac{27\sqrt 3}{2})$
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