Trigonometry (11th Edition) Clone

The hill makes an angle of $3.8^{\circ}$ with the horizontal.
Let $\theta$ be the angle the hill makes with the horizontal. The car's weight of $2800~lb$ is directed straight down. The force of $186~lb$ is directed up the hill at an angle of $\theta$ above the horizontal. We can draw a triangle with the $2800~lb$ as the hypotenuse of the triangle and the force of $186~lb$ opposite the angle $\theta$. We can find $\theta$: $sin~\theta = \frac{186}{2800}$ $\theta = arcsin(\frac{186}{2800})$ $\theta = 3.8^{\circ}$ The hill makes an angle of $3.8^{\circ}$ with the horizontal.