Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 7 - Quiz (Sections 7.1-7.3) - Page 325: 1


$A = 131.3^{\circ}$

Work Step by Step

We can use the law of sines to find $C$: $\frac{b}{sin~B} = \frac{c}{sin~C}$ $sin~C = \frac{c~sin~B}{b}$ $sin~C = \frac{4.54~sin~30.6^{\circ}}{7.42}$ $sin~C = 0.31146$ $C = arcsin(0.31146)$ $C = 18.1^{\circ}$ We can find $A$: $A+B+C = 180^{\circ}$ $A =180^{\circ}-B-C$ $A = 180^{\circ}-30.6^{\circ}-18.1^{\circ}$ $A = 131.3^{\circ}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.