## Trigonometry (11th Edition) Clone

$A = 131.3^{\circ}$
We can use the law of sines to find $C$: $\frac{b}{sin~B} = \frac{c}{sin~C}$ $sin~C = \frac{c~sin~B}{b}$ $sin~C = \frac{4.54~sin~30.6^{\circ}}{7.42}$ $sin~C = 0.31146$ $C = arcsin(0.31146)$ $C = 18.1^{\circ}$ We can find $A$: $A+B+C = 180^{\circ}$ $A =180^{\circ}-B-C$ $A = 180^{\circ}-30.6^{\circ}-18.1^{\circ}$ $A = 131.3^{\circ}$