Answer
The distance between the house and the fire is $~~7079.7~ft$
Work Step by Step
The ground coordinates of the house are $~~(x_h, y_h) = (1131.8, 4390.2)$
The ground coordinates of the fire are $~~(x_f,y_f)= (2277.5, -2596.2)$
We can find the distance between the house and the fire:
$d = \sqrt{(x_h-x_f)^2+(y_h-y_f)^2}$
$d = \sqrt{(1131.8-2277.5)^2+[4390.2-(-2596.2)]^2}$
$d = \sqrt{50122413.45}$
$d = 7079.7~ft$
The distance between the house and the fire is $~~7079.7~ft$
