## Trigonometry (11th Edition) Clone

Published by Pearson

# Chapter 7 - Applications of Trigonometry and Vectors - Section 7.1 Oblique Triangles and the Law of Sines - 7.1 Exercises - Page 305: 64b

#### Answer

The distance between the house and the fire is $~~7079.7~ft$

#### Work Step by Step

The ground coordinates of the house are $~~(x_h, y_h) = (1131.8, 4390.2)$ The ground coordinates of the fire are $~~(x_f,y_f)= (2277.5, -2596.2)$ We can find the distance between the house and the fire: $d = \sqrt{(x_h-x_f)^2+(y_h-y_f)^2}$ $d = \sqrt{(1131.8-2277.5)^2+[4390.2-(-2596.2)]^2}$ $d = \sqrt{50122413.45}$ $d = 7079.7~ft$ The distance between the house and the fire is $~~7079.7~ft$

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