## Trigonometry (11th Edition) Clone

$a = sin~A$ $b = sin~B$ $c = sin~C$
$\frac{a}{sin~A} = \frac{b}{sin~B} = \frac{c}{sin~C} = 2r$ Since the diamter is 1, the value of $2r$ is 1 $\frac{a}{sin~A} = 1$ $a = sin~A$ $\frac{b}{sin~B} = 1$ $b = sin~B$ $\frac{c}{sin~C} = 1$ $c = sin~C$