Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 6 - Inverse Circular Functions and Trigonometric Equations - Section 6.2 Trigonometric Equations I - 6.2 Exercises - Page 273: 32

Answer

$\theta = 0^{\circ}, 180^{\circ}, 360^{\circ}$

Work Step by Step

$\cos^2 \theta = \sin^2 \theta + 1$ $\cos^2 \theta - \sin^2 \theta = 1$ $\cos 2\theta = 1$ $2\theta = 0^{\circ}, 360^{\circ}, 720^{\circ}$ $\theta = 0^{\circ}, 180^{\circ}, 360^{\circ}$
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