Answer
No solution.
Work Step by Step
$\sec^2 x + 2= -1$
$(\sec x)(\sec x) = -\frac{1}{2}$
$(\frac{1}{\cos x})(\frac{1}{\cos x}) = -\frac{1}{2}$
$(\frac{1}{\cos^2 x}) = -\frac{1}{2}$
$1 = -\frac{\cos^2 x}{2}$
$-2 = \cos^2 x$
No solution.
Trigonometry (11th Edition) Clone
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
978-0-13-421743-7
ISBN 13:
978-0-13421-743-7
Chapter 6 - Inverse Circular Functions and Trigonometric Equations - Section 6.2 Trigonometric Equations I - 6.2 Exercises - Page 273: 20
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