## Trigonometry (11th Edition) Clone

$18^{\circ}$
To find the value of $\theta$, we need to substitute the value of $x=1$ in the equation and solve; $\theta=\tan^{-1}(\frac{x}{x^{2}+2})$ $\theta=\tan^{-1}(\frac{1}{1^{2}+2})$ $\theta=\tan^{-1}(\frac{1}{1+2})$ $\theta=\tan^{-1}(\frac{1}{3})$ $\theta=18.4\approx18^{\circ}$