Answer
$18^{\circ}$
Work Step by Step
To find the value of $\theta$, we need to substitute the value of $x=1$ in the equation and solve;
$\theta=\tan^{-1}(\frac{x}{x^{2}+2})$
$\theta=\tan^{-1}(\frac{1}{1^{2}+2})$
$\theta=\tan^{-1}(\frac{1}{1+2})$
$\theta=\tan^{-1}(\frac{1}{3})$
$\theta=18.4\approx18^{\circ}$
