#### Answer

The current oscillates 3 times in 0.05 seconds.

#### Work Step by Step

$V(t) = 163~sin~\omega t$
It is given in the question that the frequency is 60 cycles/second. We can find the number of oscillations in 0.05 seconds:
$(60~cycles/s)(0.05~s) = 3$
The current oscillates 3 times in 0.05 seconds.