Trigonometry (11th Edition) Clone

$$\frac{1+\tan(-\theta)}{\tan(-\theta)}=1-\cot\theta$$
$$A=\frac{1+\tan(-\theta)}{\tan(-\theta)}$$ $$A=\frac{1}{\tan(-\theta)}+\frac{\tan(-\theta)}{\tan(-\theta)}$$ $$A=\frac{1}{\tan(-\theta)}+1$$ - Negative-angle Identity: $$\tan(-\theta)=-\tan\theta$$ $$A=-\frac{1}{\tan\theta}+1$$ - Reciprocal Identity: $$\cot\theta=\frac{1}{\tan\theta}$$ $$A=-\cot\theta+1$$ $$A=1-\cot\theta$$