## Trigonometry (11th Edition) Clone

$$\tan\theta\cos\theta=\sin\theta$$
$$A=\tan\theta\cos\theta$$ - Quotient Identity: $$\tan\theta=\frac{\sin\theta}{\cos\theta}$$ Therefore, $A$ would be $$A=\frac{\sin\theta}{\cos\theta}\times\cos\theta$$ $$A=\sin\theta$$ Since no quotients appear here and all functions are of $\theta$ only, we can stop here.