Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 4 - Test - Page 193: 1e



Work Step by Step

The given graph could either be the basic secant function or the basic cosecant function. The given graph has the vertical asymptotes $x=-2\pi, -\pi, 0, \pi, 2\pi$. Since cosecant is the reciprocal of sine, and since the sine function is equal to $0$ for $x=-2\pi, -\pi, 0, \pi, 2\pi$, then the cosecant function is undefined when $x=-2\pi, -\pi, 0, \pi, 2\pi$. Therefore ,the given graph must be the graph of the cosecant function.
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