#### Answer

no solution

#### Work Step by Step

RECALL:
The range of the function $y=\sec{x}$ is $(-\infty, -1] \cup [1, \infty)$
This means that the value of the secant function is either less than or equal to $-1$ or greater than or equal to $1$.
Therefore, if $-1 \lt c \lt1$, then the equation $c=\sec{x}$ has no solution because the value of $\sec{x}$ will never be in the interval $( -1, 1)$.