## Trigonometry (11th Edition) Clone

$y=1 + \csc{x}$
The graph has a period of $2\pi$ and looks similar to the graph of the basic cosecant function. Notice, however, that instead of having the vertices at $(\frac{\pi}{2}, 1)$ and $(\frac{3\pi}{2}, -1)$, the vertices of the given graph are at $(\frac{\pi}{2}, 2)$ and $\frac{3\pi}{2}, 0)$. This means that the given graph involves a 1-unit upward shift of the parent function $y=\csc{x}$. Therefore, the equation of the function whose graph is given is $y=\csc{x} +1$ or $y=1 + \csc{x}$.