#### Answer

Refer to the graph below.

#### Work Step by Step

RECALL:
The graph of $y=a \cdot \sin{[b(x-d)]}$ has:
amplitude = $|a|$
period = $\frac{2\pi}{b}$
phase shift = $|d|$, to the left when $d\lt0$, to the right when $d\gt0$
Write the given function in the form $y=a \cdot \sin{[b(x-d)]}$ by factoring out $2$ inside the sine function to obtain:
$y=-4\sin{[2(x-\frac{\pi}{2})]}$
The given function has:
$a=-4$
$b=2$
$d=\frac{\pi}{2}$
Thus, the given function has:
amplitude = $|-4|=4$
period = $\frac{2\pi}{2} = \pi$
phase shift = $|\frac{\pi}{2}|=\frac{\pi}{2}$ to the right
Therefore, the graph of the given function has the following properties/characteristics:
amplitude = $4$ so the y-values range from $-4$ to $4$
phase shift = $\frac{\pi}{2}$ units to the right
one period interval = $[\frac{\pi}{2}, \frac{3\pi}{2}]$
Refer to the graph in the answer part above.