#### Answer

Refer to the graph below.

#### Work Step by Step

RECALL:
The graph of $y=a \cdot \sin{[b(x-d)]}$ has:
amplitude = $|a|$
period = $\frac{2\pi}{b}$
phase shift = $|d|$, to the left when $d\lt0$, to the right when $d\gt0$
The given function has:
$a=\frac{3}{2}$
$b=2$
$d=-\frac{\pi}{4}$
Thus, the given function has:
amplitude = $\frac{3}{2}$
period = $\frac{2\pi}{2} = \pi$
phase shift = $|-\frac{\pi}{4}|=\frac{\pi}{4}$ to the left
Therefore, the graph of the given function has the following properties/characteristics:
amplitude = $\frac{3}{2}$ so the y-values range from $-\frac{3}{2}$ to $\frac{3}{2}$
phase shift = $\frac{\pi}{4}$ units to the left
one period interval = $[-\frac{\pi}{4}, \frac{3\pi}{4}]$
Refer to the graph in the answer part above.