Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 3 - Test - Page 138: 20b

Answer

The angular speed of the Ferris wheel is $0.0698 ~rad/s$

Work Step by Step

The Ferris wheel rotates through an angle of $\frac{2\pi}{3}~rad$ in a time of 30 seconds. We can find the angular speed: $\omega = \frac{\theta}{t}$ $\omega = \frac{\frac{2\pi}{3}~rad}{30~s}$ $\omega = 0.0698~rad/s$ The angular speed of the Ferris wheel is $0.0698 ~rad/s$
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