Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 3 - Test - Page 138: 18c

Answer

$v = 15.7~cm/s$

Work Step by Step

We can find the linear speed $v$ of P: $v = \omega ~r$ $v = (\frac{\pi}{12}~rad/s)(60~cm)$ $v = (5\pi)~cm/s$ $v = 15.7~cm/s$
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