Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 3 - Review Exercises - Page 136: 43

Answer

$\sin{2} \gt \cos{2}$

Work Step by Step

RECALL: (1) The sine function is increasing in the interval $(0, \frac{\pi}{2})$ or $(0, 1.57)$ and decreasing in the interval $(\frac{\pi}{2}, \pi)$ or $(1.57, 3.14)$ This means that from the angle $0$ radians to $1.57$ radians, the value of the sine function increases from $0$ to $1$, while from the angle $1.57$ radians to $3.14$ radians, the value of the sine function is decreasing from $1$ to $0$. (2) The cosine function is decreasing in the interval $(0, 3.14)$, and $\cos{1.57}=0$. This means that from the angle $1.57$ radians to $3.14$ radians, the value of the cosine function approaches $-1$ Thus, $\sin{2}$ is positive while $\cos{2}$ is negative. Therefore, $\sin{2} \gt \cos{2}$.
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