## Trigonometry (11th Edition) Clone

$\tan1 \gt \sin1$
RECALL: $\tan{\theta} = \dfrac{\sin{\theta}}{\cos{\theta}}$ This means that $\tan{1} = \dfrac{\sin{1}}{\cos{1}}$. RECALL: For positive real numbers $a$ and $b$ where $0\lt b\lt 1$: $\dfrac{a}{b} \gt a$ Since $0 \lt \cos{1} \lt 1$, then $\dfrac{\sin1}{\cos1}\gt \sin1 \\\tan1 \gt \sin1$