Answer
$\tan1 \gt \sin1$
Work Step by Step
RECALL:
$\tan{\theta} = \dfrac{\sin{\theta}}{\cos{\theta}}$
This means that $\tan{1} = \dfrac{\sin{1}}{\cos{1}}$.
RECALL:
For positive real numbers $a$ and $b$ where $0\lt b\lt 1$:
$\dfrac{a}{b} \gt a$
Since $0 \lt \cos{1} \lt 1$, then
$\dfrac{\sin1}{\cos1}\gt \sin1
\\\tan1 \gt \sin1$
