Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 3 - Review Exercises - Page 136: 42


$\tan1 \gt \sin1$

Work Step by Step

RECALL: $\tan{\theta} = \dfrac{\sin{\theta}}{\cos{\theta}}$ This means that $\tan{1} = \dfrac{\sin{1}}{\cos{1}}$. RECALL: For positive real numbers $a$ and $b$ where $0\lt b\lt 1$: $\dfrac{a}{b} \gt a$ Since $0 \lt \cos{1} \lt 1$, then $\dfrac{\sin1}{\cos1}\gt \sin1 \\\tan1 \gt \sin1$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.