Answer
$47.1^{o},\qquad 132.9^{o}$
Work Step by Step
The calculator, set to DEGREES, for
$\sin^{-1}$ (0.73254290) returns
47.1000001021
$\approx 47.1^{o}$
This is the reference angle, in quadrant I.
Since sine is also positive in quadrant II,
and for $\theta$ in quadrant II, we calculate the reference angle with
$\theta^{\prime}=180^{\mathrm{o}}-\theta$,
we find the angle $\theta$ with
$\theta=180^{\mathrm{o}}-\theta^{\prime}$
$=180^{\mathrm{o}}-47.1^{o}=132.9^{o}$
