## Trigonometry (11th Edition) Clone

$\sin\theta = \frac{-\sqrt 3}{2}$ $\cos\theta = \frac{1}{2}$ $\tan\theta = -\sqrt 3$ $\csc\theta = \frac{-2\sqrt 3}{3}$ $\sec\theta = 2$ $\cot\theta = \frac{-\sqrt 3}{3}$
1. $\theta = 1020^{\circ}$ The angle lies in the IV quadrant and reference angle is $60^{\circ}$ because $3\times 360^{\circ} - 1020 = 60$ 2. In IV quadrant $cos\theta$ and $\sec\theta$ are positive, and remaining functions will be negative 3. $\sin\theta = -sin 60^{\circ} = \frac{-\sqrt 3}{2}$ $\cos\theta =cos 60^{\circ} = \frac{1}{2}$ $\tan\theta =-\tan 60^{\circ} = -\sqrt 3$ $\csc\theta =-\csc 60^{\circ} = \frac{-2\sqrt 3}{3}$ $\sec\theta = \sec 60^{\circ} = 2$ $\cot\theta = -\cot 60^{\circ} = \frac{-\sqrt 3}{3}$