## Trigonometry (11th Edition) Clone

$a\approx 310.8 ft$ $b \approx 230.8 ft$ $\angle B = 36^{\circ} 36'$
1.Given $A = 53^{\circ} 24' = 53. 4 ^{\circ}$ (converted to degrees for further calcualation) and$c = 387.1 ft$ 2. Use sine to find $a$ $\sin 53.4^{\circ} = \frac{a}{387.1}$ => $a\approx310.8 ft$ 3. Use cosine to find side $b$ $\cos 53.4^{\circ} = \frac{b}{387.1}$ => $b \approx 230.8 ft$ 4. Angles in a triable add up to 180 degrees, therefore $\angle B = 180^{\circ} -90^{\circ} -53.4^{\circ} = 36.6^{\circ}\approx 36^{\circ} 36'$ converted into minutes with 4 significant figures, corresponding given values