Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 2 - Acute Angles and Right Triangles - Section 2.4 Solving Right Triangles - 2.4 Exercises - Page 78: 34

Answer

$\angle A = 63^{\circ}$ $\angle B = 27^{\circ}$ $c\approx 1076m$

Work Step by Step

1. $b = 489m$ and $a =958m$ 2. $\angle B = \tan^{-1} \frac{489}{958} = 27^{\circ}$ 3. $\cos 27^{\circ} =\frac{958}{c}$ $c \approx 1076m$ 4. $\angle A = 180^{\circ} -90^{\circ} -27 ^{\circ} = 63^{\circ}$ 5. Answers 2 significant figures and angles in minute $\angle A= 63^{\circ}$ and $\angle B = 27^{\circ}$
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