Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 2 - Acute Angles and Right Triangles - Section 2.4 Solving Right Triangles - 2.4 Exercises - Page 77: 6

Answer

E

Work Step by Step

$x=5\sec 38^{\circ}\implies \sec38^{\circ}=\frac{x}{5}$ But $\sec\theta=\frac{\text{hypotenuse}}{\text{adjacent side}}$ This implies that $5$ is the length of the adjacent side to the $38^{\circ}$ angle and the length of the hypotenuse is $x$. This is the case in triangle E.
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