Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 2 - Acute Angles and Right Triangles - Section 2.4 Solving Right Triangles - 2.4 Exercises - Page 77: 1

Answer

B

Work Step by Step

$x=5\cot 38^{\circ}\implies \cot 38^{\circ}=\frac{x}{5}$ But $\cot\theta=\frac{\text{adjacent side}}{\text{hypotenuse}}$ This implies that $x$ is the length of the adjacent side to the $38^{\circ}$ angle and the length of the side opposite to it is 5. This is the case in triangle B.
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